Java：创建一个以字母为索引的数组 [英] Java: Create an array with letter characters as index

问题描述

是否可以在Java中创建一个由字母字符（'a'到'z'）而不是整数编制索引的数组？

Is it possible to create in Java an array indexed by letter characters ('a' to 'z') rather than by integers?

使用这样的数组一个，我想以这种方式使用，例如

With such an array "a", I would like to useit in this way, for example

print (a['a']);

推荐答案

使用地图代替。

Map<Character, Object> myMap = new HashMap<Character, Object>();
myMap.put('a', something);

print(myMap.get('a'));

另一方面，正如其他人已经建议的那样，你可以使用char作为索引（但你会保留所有数组元素 0 ...'a'-1 为空）：

On the other hand, as others already suggested, you can use a char as index (but you would leave all array elements 0...'a'-1 empty):

String[] a = new String['z' + 1];
a['a'] = "Hello World";
System.out.println(a['a']);

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