Python super（Class，self）.method vs super（Parent，self）.method [英] Python super(Class, self).method vs super(Parent, self).method

问题描述

这个问题来自以下问题，让我们说 B类 extends A类

This question is derive from the following question, let's say class B extends class A

class A(object):
  def do_work(self):
    print 123

class B(A):
  def do_work(self):
    super(B,self).do_work() # versus the next statement
    super(A,self).do_work() # what's the difference?

推荐答案

super(B,self).do_work()

将调用 do_work 由 B 的父类看到的函数 - 即 A.do_work 。

will call the do_work function as seen by the parent class of B - that is, A.do_work.

super(A,self).do_work()

将调用 do_work 函数，如<$ c $的父类所示c> A - 即 object.do_work （可能不存在，因此可能引发异常）。

will call the do_work function as seen by the parent class of A - that is, object.do_work (which probably doesn't exist, and thus would likely raise an exception).

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