Pandas:减去两个日期列,结果为整数 [英] Pandas: Subtracting two date columns and the result being an integer
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问题描述
我在Pandas数据框中有两列是日期。
I have two columns in a Pandas data frame that are dates.
我希望从另一列中减去一列,结果是天数作为整数的差异。
I am looking to subtract one column from another and the result being the difference in numbers of days as an integer.
查看数据:
df_test.head(10)
Out[20]:
First_Date Second Date
0 2016-02-09 2015-11-19
1 2016-01-06 2015-11-30
2 NaT 2015-12-04
3 2016-01-06 2015-12-08
4 NaT 2015-12-09
5 2016-01-07 2015-12-11
6 NaT 2015-12-12
7 NaT 2015-12-14
8 2016-01-06 2015-12-14
9 NaT 2015-12-15
我已成功创建了一个新列,区别于:
I have created a new column successfully with the difference:
df_test['Difference'] = df_test['First_Date'].sub(df_test['Second Date'], axis=0)
df_test.head()
Out[22]:
First_Date Second Date Difference
0 2016-02-09 2015-11-19 82 days
1 2016-01-06 2015-11-30 37 days
2 NaT 2015-12-04 NaT
3 2016-01-06 2015-12-08 29 days
4 NaT 2015-12-09 NaT
但是我无法获得结果的数字版本:
However I am unable to get a numeric version of the result:
df_test['Difference'] = df_test[['Difference']].apply(pd.to_numeric)
df_test.head()
Out[25]:
First_Date Second Date Difference
0 2016-02-09 2015-11-19 7.084800e+15
1 2016-01-06 2015-11-30 3.196800e+15
2 NaT 2015-12-04 NaN
3 2016-01-06 2015-12-08 2.505600e+15
4 NaT 2015-12-09 NaN
推荐答案
您可以划分 dtype
timedelta
by np.timedelta64(1,'D')
,但输出不是 int
,但 float
,因为 NaN
值:
You can divide column of dtype
timedelta
by np.timedelta64(1, 'D')
, but output is not int
, but float
, because NaN
values:
df_test['Difference'] = df_test['Difference'] / np.timedelta64(1, 'D')
print (df_test)
First_Date Second Date Difference
0 2016-02-09 2015-11-19 82.0
1 2016-01-06 2015-11-30 37.0
2 NaT 2015-12-04 NaN
3 2016-01-06 2015-12-08 29.0
4 NaT 2015-12-09 NaN
5 2016-01-07 2015-12-11 27.0
6 NaT 2015-12-12 NaN
7 NaT 2015-12-14 NaN
8 2016-01-06 2015-12-14 23.0
9 NaT 2015-12-15 NaN
频率转换。
这篇关于Pandas:减去两个日期列,结果为整数的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
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