C ++中的int64和int64_t有什么区别？ [英] What is the difference between int64 and int64_t in C++?

问题描述

我是c ++和编码的新手。所以这个问题可能是愚蠢的。使用int64或int64_t类型有什么区别。我看到其中一个软件开发人员在github上修改了他们的源代码，并将所有的int64修改为int64_t。

I am new to c++ and coding in general. so this question might be noobish. what is the difference in using type int64 or int64_t. I saw that one of the software devs modified their source on github and all of the int64 to int64_t.

推荐答案

int64_t 是标准C ++类型，用于完全64位的有符号整数。 int64 不是标准类型。

int64_t is a Standard C++ type for a signed integer of exactly 64 bits. int64 is not a standard type.

第一个C ++标准没有固定宽度类型。在将 int64_t 添加到标准C ++之前，不同的编译器都实现了64位类型，但它们使用了自己的名称（例如 long long ， __ int64 等。）

The first C++ standard didn't have fixed-width types. Before int64_t was added to Standard C++, the different compilers all implemented a 64-bit type but they used their own names for it (e.g. long long, __int64, etc.)

一系列可能的事件是这个项目最初的对于支持的每个编译器，将 typedef int64 改为64位类型。但是，一旦编译器开始更好地支持标准C ++，或者编写代码的人发现 int64_t ，代码就会被切换为使用标准名称。

A likely series of events is that this project originally would typedef int64 to the 64-bit type for each compiler it was supported on. But once compilers all started to support Standard C++ better, or once the person who wrote the code found out about int64_t, the code was switched over to use the standard name.

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