如何在java中输出无符号整数的绝对值 [英] How to output the absolute value of an Unsigned integer in java

问题描述

我想将 4294967295 分配给变量（ 2 ^ 32-1 ）
它是很明显，我不能用 Integer 来做到这一点，并且可以用 Long 来做。

I want to assign 4294967295 to a variable (2^32-1) It is obvious that I can't do that with Integer, and can do it with Long.

但是，我注意到Java 8提供了无符号整数（至少有一些方法）。

However, I noted that Java 8 offers Unsigned Integers (at least some methods).

有没有人知道方法是什么， Integer.parseUnsignedInt（）呢？
当我输入4294967295并打印变量时，它输出为 -1
（ -2 > 4294967294 ， -3 for 4294967293 依此类推......）

Does any one know what the method, Integer.parseUnsignedInt() does? When I input "4294967295" to that, and print the variable, it gives the output as -1 (-2 for 4294967294, -3 for 4294967293 and so on...)

有没有办法我仍然可以 4294967295 在变量中？

Is there a way that I can still have 4294967295 in a variable?

我在这里遗漏了什么吗？

Am I missing something here?

a=Integer.parseUnsignedInt("4294967295");
System.out.println(a);

这使得输出为 -1 但是我期望 4294967295 。

This gives the output as -1 but I expected 4294967295.

推荐答案

您可以将该整数视为unsigned int通过调用 toUnsignedString（）：

You can view that integer as unsigned int by calling toUnsignedString():

int uint = Integer.parseUnsignedInt("4294967295");
System.out.println(Integer.toUnsignedString(uint));

您还可以调用其他一些将int解释为unsigned的方法。

You can also call some other methods that interpret that int as unsigned.

例如：

long l = Integer.toUnsignedLong(uint);
System.out.println(l); // will print 4294967295

int x = Integer.parseUnsignedInt("4294967295");
int y = 5;
int cmp1 = Integer.compareUnsigned(x,y); // interprets x as 4294967295 (x>y) 
int cmp2 = Integer.compare(x,y); // interprets x as -1 (x<y) 

这篇关于如何在java中输出无符号整数的绝对值的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！