在C中存储以零开头的值变异，为什么？ [英] In C storing values that start with zero get mutated, why?

问题描述

例如：

int main(){

    int x = 01234567;

    printf("\n%d\n",x);

    return 0;

}

以下代码生成：342391

The following code produces: 342391

如果我在开头没有包含0，那么值x将是1234567，为什么C以这种方式存储值并且有没有办法让它不这样做？

If I didn't include the 0 at the beginning, the value x would be 1234567, why does C store the value this way and is there any way to get it from not doing this?

推荐答案

因为以0开头的数字表示为八进制数。你无法真正修改这种行为，只是不要在开头包含零。

Because numbers starting with 0 are represented as octal numbers. You cannot really modify this behavior, simply do not include the zero at the beginning.

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