在java中难以读取整数?它背后有什么理由吗? [英] Hard to read integers in java? Is there any reason behind it?

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问题描述

我必须在Java中更频繁地读取整数。那我该怎么办?我必须使用什么功能?

I have to read integers more frequently in Java. So how i should do? What function i have to use?

C / C ++也有缓冲概念,但它们只有一个语句。但是在Java中我们必须调用至少2个函数来读取整数。

C/C++ too have buffering concepts but they has a single statement. But in Java we have to call at least 2 function to read an integer.

例如,

要从控制台读取整数,

我将使用


  • scanf in C

  • cin in C ++

  • scanf in C
  • cin in C++

但在Java中,

BufferedReader bufferedreader = new BufferedReader(
    new InputStreamReader(System.in)); String number = bufferedreader.readLine();

int value = Integer.parseInt(number);

Scanner scan = new Scanner(System.in); 
int i = scan.nextInt();

有人请解释一下:我能否拥有比更简单的版本? cin scanf (单行声明)。

Someone please explain me: Can I have a simpler version than these similar to cin or scanf (A one line statement).

提前致谢。

推荐答案

我相信 Scanner 提供最简单的界面。我不相信标准API提供了更简单的方法。 (你当然可以将片段封装在一个方法中,然后调用该方法。)

I believe Scanner provides the simplest interface. I don't believe there is a simpler approach provided by the standard API. (You could of course encapsulate the snippet in a method, and call the method instead.)

我能想出的唯一一个明显的

The only one-liner I can come up with is the obvious

int i = new Scanner(System.in).nextInt();

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