Int列表上的Python位操作 [英] Python Bit Operations on a list of Int's

问题描述

我想做的事情不起作用：
整体清单......

What I want to do that does not work: List of ints...

BebossArray=[0 for i in xrange(1024)]

我的位功能（有通常的设置，清除，切换，测试，但这里设置）

My bit functions (There are all the usual set,clear,toggle, test but here is set)

def setBit(dint, offset):
mask = 1 << offset
dint=(dint|mask)
return

所以我想要在列表中的一个整数中设置一个位...

so I would like to set a bit in one of the ints in the list...

setBit(DebossArray[index],3)

这当然不起作用。 setBit中的赋值只是创建一个新对象，DebossArray [index]按预期保持put。所以我认为INT是不可改变的，所以我不能做出改变。

This, of course, does not work. The assignment in setBit just creates a new object and DebossArray[index] stays put as expected. So I get that INT's are immuttable so I can't do a change in place.

我做了什么......（我不喜欢它，但它适用于我的目的）

What I did... (I don't like it but it works for my purposes)

DebossArray=[ctypes.c_int32() for x in xrange(1024)]

和

def setBit(dint, offset):
mask = 1 << offset
dint.value=(dint.value|mask)
return

所以现在

setBit(DebossArray[index],3]

按预期工作，因为ctype.c_int32（）是可变的，所以我可以在适当的位置修改它。

works as expect because ctype.c_int32() IS mutable so I can modify it in place.

我是使用2.7但最多滚动3可能会在项目后期发生。我也试图远离

I am using 2.7 but rolling up to 3 will probably happen later in the project.I am also trying to stay away from

DebossArray[index]=setBit(DebossArray[index],3)

构造类型。

更多细节：
在某些地方我有DebossArray [x]而在其他地方我有ButtonArray [x] [y]

More detail: In some places I have DebossArray[x] and in other places I have ButtonArray[x][y]

现在到了这一点;
这样做的正确方法是什么？

And now to the point; What is the correct way to do this?

推荐答案

我想你重复这一点，只需返回结果并重新绑定原始名称：

I think you're over complicating this, just return the result and rebind the original name:

def setBit(dint, offset):
    mask = 1 << offset
    return dint | mask

r = 0
r = setBit(r, 5)
# 32

你没有真的甚至需要一个功能，你可以做：

You don't really even need a function, you could just do:

i = 0
i |= (1 << 5)
# 32

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