在Python中将字符串转换为带小数的整数 [英] Convert a string to integer with decimal in Python

问题描述

我有一个格式的字符串：Python中的'nn.nnnnn'，我想将它转换为整数。

I have a string in the format: 'nn.nnnnn' in Python, and I'd like to convert it to an integer.

直接转换失败：

>>> s = '23.45678'
>>> i = int(s)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: invalid literal for int() with base 10: '23.45678'

我可以使用以下代码将其转换为小数：

I can convert it to a decimal by using:

>>> from decimal import *
>>> d = Decimal(s)
>>> print d
23.45678

我也可以拆分'。'，然后从中减去小数零，然后将其添加到整数... yuck。

I could also split on '.', then subtract the decimal from zero, then add that to the whole number ... yuck.

但我更喜欢将它作为int，没有不必要的类型转换或机动。

But I'd prefer to have it as an int, without unnecessary type conversions or maneuvering.

推荐答案

这个怎么样？

>>> s = '23.45678'
>>> int(float(s))
23

或...

>>> int(Decimal(s))
23

或...

>>> int(s.split('.')[0])
23

我怀疑我担心会比这简单得多。接受它并继续前进。

I doubt it's going to get much simpler than that, I'm afraid. Just accept it and move on.

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