Python - 将一串数字转换为int列表 [英] Python - converting a string of numbers into a list of int

问题描述

我有一串数字，例如：

example_string = '0, 0, 0, 11, 0, 0, 0, 0, 0, 19, 0, 9, 0, 0, 0, 0, 0, 0, 11'

我想将此转换为列表：

example_list = [0, 0, 0, 11, 0, 0, 0, 0, 0, 19, 0, 9, 0, 0, 0, 0, 0, 0, 11]

我在示例字符串中尝试了类似

I tried something like

for i in example string:
    example_list.append(int(example_string[i]))

但这显然不起作用，因为字符串包含空间和昏迷。但是，删除它们不是一种选择，因为像19这样的数字会转换为1和9.你能帮我解决这个问题吗？

but this obviously does not work as the string contains spaces and comas. However, removing them is not an option, as numbers like '19' would be converted to 1 and 9. Could you please help me with this?

推荐答案

在逗号上拆分，然后映射到整数：

Split on commas, then map to integers:

map(int, example_string.split(','))

或使用列表理解：

[int(s) for s in example_string.split(',')]

如果你想要一个列表结果，后者在Python 3上效果更好。

The latter works better on Python 3 if you want a list result.

这是因为 int（）容忍空格：

>>> example_string = '0, 0, 0, 11, 0, 0, 0, 0, 0, 19, 0, 9, 0, 0, 0, 0, 0, 0, 11'
>>> map(int, example_string.split(','))
[0, 0, 0, 11, 0, 0, 0, 0, 0, 19, 0, 9, 0, 0, 0, 0, 0, 0, 11]
>>> [int(s) for s in example_string.split(',')]
[0, 0, 0, 11, 0, 0, 0, 0, 0, 19, 0, 9, 0, 0, 0, 0, 0, 0, 11]

分裂只是 a逗号也更容忍变量输入;如果值之间使用0,1或10个空格并不重要。

Splitting on just a comma also is more tolerant of variable input; it doesn't matter if 0, 1 or 10 spaces are used between values.

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