php：'0'为空字符串（） [英] php: '0' as a string with empty()

问题描述

我想将0视为一个整数，将'0'视为字符串，但是empty（）在下面的示例中将'0'视为字符串，

I want a 0 to be considered as an integer and a '0' to be considered as a string but empty() considers the '0' as a string in the example below,

$var = '0';

// Evaluates to true because $var is empty
if (empty($var)) {
    echo '$var is empty';
}

我如何'使'empty（）将'0'作为字符串？

how can I 'make' empty() to take '0's as strings?

谢谢。

推荐答案

你做不到。这就是它的设计方式。相反，你可以写一个和语句进行测试：

You cannot make it. That is how it was designed. Instead you can write an and statement to test:

if (empty($var) && $var !== '0') {
    echo $var . ' is empty';
}

您可以使用 isset ，当然，除非您希望它拒绝其他空箱，空检查。

You could use isset, unless of course, you want it to turn away the other empties, that empty checks for.

编辑

修复了检查以进行类型检查，这要归功于2371指出的那样：）

Fixed the check to do a type check as well, thanks to the 2371 for pointing that out :)

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