Swift将UInt转换为Int [英] Swift convert UInt to Int
本文介绍了Swift将UInt转换为Int的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有这个表达式返回 UInt32
:
let randomLetterNumber = arc4random()%26
我希望能够使用此if语句中的数字:
I want to be able to use the number in this if statement:
if letters.count > randomLetterNumber{
var randomLetter = letters[randomLetterNumber]
}
这个问题是控制台给我这个
This issue is that the console is giving me this
Playground execution failed: error: <REPL>:11:18: error: could not find an overload for '>' that accepts the supplied arguments
if letters.count > randomLetterNumber{
~~~~~~~~~~~~~~^~~~~~~~~~~~~~~~~~~~
问题是 UInt32
无法与 Int
。我想将 randomLetterNumber
转换为 Int
。我试过了:
The problem is that UInt32
cannot be compared to an Int
. I want to cast randomLetterNumber
to an Int
. I have tried:
let randomLetterUNumber : Int = arc4random()%26
let randomLetterUNumber = arc4random()%26 as Int
这两个原因找不到'%'的重载接受提供的参数。
如何转换值或在if语句中使用它?
How can I cast the value or use it in the if statement?
推荐答案
Int(arc4random_uniform(26))
做两件事,一件它消除了当前方法的负面结果,其次应该从结果中正确创建一个Int。
Int(arc4random_uniform(26))
does two things, one it eliminates the negative results from your current method and second should correctly creat an Int from the result.
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