如何将NSTimeInterval转换为int？ [英] How to convert NSTimeInterval to int?

问题描述

如何将NSTimeInterval转换为整数值？

How do I convert NSTimeInterval into an Integer value?

我的TimeInterval保存值 83.01837 。我需要将其转换为 83 。我用谷歌搜索但找不到任何帮助。

My TimeInterval holds the value 83.01837. I need to convert it into 83. I have googled but couldn't find any help.

推荐答案

直接分配：

NSTimeInterval interval = 1002343.5432542;
NSInteger time = interval;
//time is now equal to 1002343

NSTimeInterval是一个双倍，所以如果你指定它直接到NSInteger（或int，如果你愿意）它会工作。这将把时间缩短到最接近的秒数。

NSTimeInterval is a double, so if you assign it directly to a NSInteger (or int, if you wish) it'll work. This will cut off the time to the nearest second.

如果你希望四舍五入到最接近的秒（而不是切断它），你可以在制作之前使用圆形作业：

If you wish to round to the nearest second (rather than have it cut off) you can use round before you make the assignment:

NSTimeInterval interval = 1002343.5432542;
NSInteger time = round(interval);
//time is now equal to 1002344

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