是否有标准整数类型，其大小为模板参数？ [英] Are there standard integer types with sizes being template parameters?

问题描述

假设我需要制作一个模板，其成员长度为 N 位，其中 N 是模板参数。我当然可以定义这样的东西

Suppose I need to make a template with a member of exactly N bits in length, where N is the template parameter. I could of course define something like this

#include <cstdint>
template<int N>
struct sized_uint {};
template<> struct sized_uint<8> { typedef uint8_t type; };
template<> struct sized_uint<16> { typedef uint16_t type; };
template<> struct sized_uint<32> { typedef uint32_t type; };
template<> struct sized_uint<64> { typedef uint64_t type; };

然后在我的模板中使用它，例如函数：

and then use it in my template for e.g. a function:

template<int N> void myfunc(typename sized_uint<N>::type);

但是有没有像上面定义的那样的标准类型 sized_uint 在任何版本的C ++中？

But are there any standard types like the above defined sized_uint in any version of C++?

推荐答案

没有类似的标准类型。但是，有 boost :: int_t ，如果你想要的话，它会做你想要的你可以接受提升依赖性。请注意，语义略有不同，因为 boost :: int_t 将为您提供最小的整数类型，至少那么多位，而不是正好那么多。

There is no standard type like that. However, there is boost::int_t, which will do what you want if the boost dependency is acceptable for you. Note that the semantics are slightly different, in that boost::int_t will give you the smallest integral type with at least that many bits, rather than exactly that many.

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