我们如何在java中创建接口对象？ [英] How can we create object of interface in java?

问题描述

这段代码是如何工作的我完全感到困惑....

How is this code working i m totally puzzled....

package com.servletpack.examples;

interface check {
    public void message();
}
public class Interface {
    public static void main(String[] args) {
        try {
            check t = new check() {//how????????????????
                public void message() {
                    System.out.println("Method defined in the interface");
                }
            };
            t.message();
        } catch (Exception ex) {
            System.out.println("" + ex.getMessage());
        }
    }
}

推荐答案

使用该语法，您可以创建匿名类 ，这是完全合法的。

With that syntax, you create an anonymous class, which is perfectly legal.

在内部，匿名类被编译为自己的类，称为 EnclosingClass $ n 封闭类的名称在 $ 符号之前。和每个额外的匿名类增加 n 。这意味着正在创建以下类：

Internally, anonymous classes are compiled to a class of their own, called EnclosingClass$n where the enclosing class' name precedes the $ sign. and n increases for each additional anonymous class. This means that the following class is being created:

class Interface$1 implements check {
     public void message() {
         System.out.println("Method defined in the interface");
     }
}

然后，中的代码main 编译为在内部使用新定义的匿名类：

Then, the code in main compiles to internally use the newly-defined anonymous class:

check t = new Interface$1();
t.message();

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