为什么嵌套接口隐式声明为静态? [英] Why are nested interfaces declared implicitly static?
问题描述
正如标题所说,为什么嵌套接口是隐式静态的。为什么我不能像嵌套类一样使用嵌套接口,例如静态和无静态
从 oracle文档:
内部类与其封闭类
的实例相关联,并且可以直接访问该对象的方法和字段
ie它保持对其封闭实例的引用。
另一个接口,它只是类型的静态定义。一个契约,用于提供一些多态性。
接口本身不能被实例化,因此它不能具有状态,因此它无法知道封闭的实例。 / p>
as the title says, why nested interfaces are implicitly static.Why cant i use nested interfaces just like nested classes ie like with static and without static
From the oracle documentation:
an inner class is associated with an instance of its enclosing class and has direct access to that object's methods and fields
i.e. it maintains a reference to its enclosing instance.
An interface on the other and is just a static definition of type. A contract, used to provide some polymorphism.
An interface cannot itself be instantiated, therefor it cannot have state, and thus it cannot "know" about an enclosing instance.
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