如何以编程方式获取资源目录路径 [英] How to get resources directory path programmatically

问题描述

我有以下目录布局：

• src
  
  
  
  • main
    
    
    
    
    • java
    
    
    • 资源
      
      
      
      
      • sql（数据库脚本）
      
      
      • spring（配置）
      
      

在ServletContextListener类中，我想访问SQL目录下的文件并列出它们。基本上我的问题是路径，因为我知道简单地列出目录下的文件是：

Within a ServletContextListener class, I want to access the files under the SQL directory and list them. Basically my problem is with the path, because I know that listing files under a directory in a nutshell is:

File folder = new File(path);
File[] listOfFiles = folder.listFiles();

也许我可以使用 ServletContextEvent 对象来尝试构建 resources / sql的路径

Maybe I could use the ServletContextEvent Object to try and build a path to resources/sql

public void contextInitialized(ServletContextEvent event) {
    event.getServletContext(); //(getRealPath etc.)
}

是否存在设置该路径的内容相对的，非硬编码的方式？
像新文件（classpath：sql）（最好是弹簧，如果可能的话）或者我应该怎么做servletContext指向 resources / sql ？

Does something exist to set that path in a relative, non-hardcoded way? Something like new File("classpath:sql") (preferably spring if possible) or what should I do with the servletContext to point at resources/sql?

推荐答案

我假设的内容src / main / resources / 在构建时复制到.war内的 WEB-INF / classes / 。如果是这种情况你可以这样做（用实数值代替类名和被加载的路径）。

I'm assuming the contents of src/main/resources/ is copied to WEB-INF/classes/ inside your .war at build time. If that is the case you can just do (substituting real values for the classname and the path being loaded).

URL sqlScriptUrl = MyServletContextListener.class
                       .getClassLoader().getResource("sql/script.sql");

这篇关于如何以编程方式获取资源目录路径的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！