Ionic 2 - 如何返回给定选项卡的起始页面 [英] Ionic 2 - How do I get back to the start page of a given tab

问题描述

我的APP使用标签，在这些标签内我有按钮，使用 push 打开其他页面，当我点击标签2，然后点击按钮时，它会打开正常页面，然后我单击选项卡1，然后再次单击选项卡2，但它没有显示选项卡2的开始页面，它已经打开了我之前点击过的页面...我该如何制作它每次单击选项卡时，它都会显示该选项卡的页面，并且不会打开我访问过的页面？我尝试使用 this.tabRef.select（0）; 在tab.ts内部，但双击每个标签的第一次点击，这会导致屏幕闪烁通过两次调用将它留空几秒钟...我尝试了 this.navCtrl.setRoot（HomePage）; ，但是它会将标签从屏幕上取下来，因为它将HomePage作为主页。

My APP works with tabs, inside these tabs I have buttons that open other pages using push, when I click on tab 2, and click on a button, it opens the normal page, then I click on tab 1, and then click again in tab 2, but instead of showing the start page of tab 2, it already comes open with the page that I had clicked before ... How do I make it every time it clicks on a tab, it shows exactly the Page of that tab, and do not bring the page I had visited open? I tried using this.tabRef.select (0); Inside the tab.ts but it double-clicks on the first click of each tab, which causes a blink on the screen leaving it blank for a few seconds by calling it twice ... I tried this.navCtrl.setRoot (HomePage ) ;, but it takes the tabs off the screen, as it takes HomePage as the home page.

推荐答案

在标签的子页面中使用此代码：

Use this code in child pages of tab:

ionViewDidLeave(){
   this.navController.setRoot(/*your tab page*/);
}

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