如何确定当前的iPhone /设备型号? [英] How to determine the current iPhone/device model?

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问题描述

有没有办法在Swift中获取设备型号名称(iPhone 4S,iPhone 5,iPhone 5S等)?

Is there a way to get the device model name (iPhone 4S, iPhone 5, iPhone 5S, etc) in Swift?

我知道有一个名为的属性 UIDevice.currentDevice()。model 但它只返回设备类型(iPod touch,iPhone,iPad,iPhone模拟器等)。

I know there is a property named UIDevice.currentDevice().model but it only returns device type (iPod touch, iPhone, iPad, iPhone Simulator, etc).

我也知道可以使用这种方法在Objective-C中轻松完成:

I also know it can be done easily in Objective-C with this method:

#import <sys/utsname.h>

struct utsname systemInfo;
uname(&systemInfo);

NSString* deviceModel = [NSString stringWithCString:systemInfo.machine
                          encoding:NSUTF8StringEncoding];

但是我正在Swift中开发我的iPhone应用程序,所以有人可以用同样的方式帮助我在Swift中解决这个问题?

But I'm developing my iPhone app in Swift so could someone please help me with the equivalent way to solve this in Swift?

推荐答案

我在 UIDevice

此版本适用于Swift 2或更高版本
如果您使用的是早期版本,请使用我的答案的旧版本

如果您正在寻找更多优雅的解决方案,您可以使用我的μ-framework DeviceKit 发表于GitHub(也可通过CocoaPods,Carthage和Swift Package Manager获得)。

If you are looking for a more elegant solution you can use my µ-framework DeviceKit published on GitHub (also available via CocoaPods, Carthage and Swift Package Manager).

以下是代码:

import UIKit

public extension UIDevice {

    static let modelName: String = {
        var systemInfo = utsname()
        uname(&systemInfo)
        let machineMirror = Mirror(reflecting: systemInfo.machine)
        let identifier = machineMirror.children.reduce("") { identifier, element in
            guard let value = element.value as? Int8, value != 0 else { return identifier }
            return identifier + String(UnicodeScalar(UInt8(value)))
        }

        func mapToDevice(identifier: String) -> String { // swiftlint:disable:this cyclomatic_complexity
            #if os(iOS)
            switch identifier {
            case "iPod5,1":                                 return "iPod Touch 5"
            case "iPod7,1":                                 return "iPod Touch 6"
            case "iPhone3,1", "iPhone3,2", "iPhone3,3":     return "iPhone 4"
            case "iPhone4,1":                               return "iPhone 4s"
            case "iPhone5,1", "iPhone5,2":                  return "iPhone 5"
            case "iPhone5,3", "iPhone5,4":                  return "iPhone 5c"
            case "iPhone6,1", "iPhone6,2":                  return "iPhone 5s"
            case "iPhone7,2":                               return "iPhone 6"
            case "iPhone7,1":                               return "iPhone 6 Plus"
            case "iPhone8,1":                               return "iPhone 6s"
            case "iPhone8,2":                               return "iPhone 6s Plus"
            case "iPhone9,1", "iPhone9,3":                  return "iPhone 7"
            case "iPhone9,2", "iPhone9,4":                  return "iPhone 7 Plus"
            case "iPhone8,4":                               return "iPhone SE"
            case "iPhone10,1", "iPhone10,4":                return "iPhone 8"
            case "iPhone10,2", "iPhone10,5":                return "iPhone 8 Plus"
            case "iPhone10,3", "iPhone10,6":                return "iPhone X"
            case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return "iPad 2"
            case "iPad3,1", "iPad3,2", "iPad3,3":           return "iPad 3"
            case "iPad3,4", "iPad3,5", "iPad3,6":           return "iPad 4"
            case "iPad4,1", "iPad4,2", "iPad4,3":           return "iPad Air"
            case "iPad5,3", "iPad5,4":                      return "iPad Air 2"
            case "iPad6,11", "iPad6,12":                    return "iPad 5"
            case "iPad7,5", "iPad7,6":                      return "iPad 6"
            case "iPad2,5", "iPad2,6", "iPad2,7":           return "iPad Mini"
            case "iPad4,4", "iPad4,5", "iPad4,6":           return "iPad Mini 2"
            case "iPad4,7", "iPad4,8", "iPad4,9":           return "iPad Mini 3"
            case "iPad5,1", "iPad5,2":                      return "iPad Mini 4"
            case "iPad6,3", "iPad6,4":                      return "iPad Pro 9.7 Inch"
            case "iPad6,7", "iPad6,8":                      return "iPad Pro 12.9 Inch"
            case "iPad7,1", "iPad7,2":                      return "iPad Pro 12.9 Inch 2. Generation"
            case "iPad7,3", "iPad7,4":                      return "iPad Pro 10.5 Inch"
            case "AppleTV5,3":                              return "Apple TV"
            case "AppleTV6,2":                              return "Apple TV 4K"
            case "AudioAccessory1,1":                       return "HomePod"
            case "i386", "x86_64":                          return "Simulator \(mapToDevice(identifier: ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] ?? "iOS"))"
            default:                                        return identifier
            }
            #elseif os(tvOS)
            switch identifier {
            case "AppleTV5,3": return "Apple TV 4"
            case "AppleTV6,2": return "Apple TV 4K"
            case "i386", "x86_64": return "Simulator \(mapToDevice(identifier: ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] ?? "tvOS"))"
            default: return identifier
            }
            #endif
        }

        return mapToDevice(identifier: identifier)
    }()

}

你这样称呼它:

let modelName = UIDevice.modelName

对于真实设备,它返回例如iPad Pro 9.7英寸,对于模拟器,它返回模拟器+模拟器标识符,例如模拟器iPad Pro 9.7英寸

For real devices it returns e.g. "iPad Pro 9.7 Inch", for simulators it returns "Simulator " + Simulator identifier, e.g. "Simulator iPad Pro 9.7 Inch"

这篇关于如何确定当前的iPhone /设备型号?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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