在Xcode中使用GPX来模拟位置变化时，有没有办法控制速度？ [英] When using GPX in Xcode to simulate location changes, is there a way to control the speed?

问题描述

我在Xcode 4.2中使用以下GPX文件来模拟位置更改。它运作良好，但我无法控制位置变化的速度。邮票似乎不起作用。有没有人有这方面的解决方案？

I'm using the following GPX file in Xcode 4.2 to simulate a location change. It works well, but I can't control the speed of the location change. stamp seems to be not working. Does anyone have a solution for this?

<?xml version="1.0"?>
<gpx version="1.1" creator="Xcode"> 
    <wpt lat="37.331705" lon="-122.030237"></wpt>
    <wpt lat="37.331705" lon="-122.030337"></wpt>
    <wpt lat="37.331705" lon="-122.030437"></wpt>
    <wpt lat="37.331705" lon="-122.030537"></wpt>
</gpx>

推荐答案

我不认为（知道）这是可以直接在GPX中使用，但您可以使用Instruments / Automation测试位置更改。

I don't think (know) that this is possible in the GPX directly, but you can test location change with Instruments/Automation.

您可以使用如下脚本：

var target = UIATarget.localTarget();
target.setLocation(<location);
target.delay(5);
target.setLocation(...);

依此类推。我从WWDC11视频中采用了这个示例 https://developer.apple.com/videos / play / wwdc2011 / 518 / （测试位置感知应用程序）

And so on. I took this example from the WWDC11 video https://developer.apple.com/videos/play/wwdc2011/518/ (Testing your location-aware applications)

我知道这实际上并不能让你定义速度，但是我希望延迟能以某种方式解释。也许那会对你有所帮助。

I'm aware that this doesn't actually let you define the speed, but the delays somehow account for that I hope. Maybe that'll help you.

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