如何注册应用程序以响应自定义URL方案打开请求？ [英] How to register an app to respond to a custom URL scheme opening request?

问题描述

喜欢这样：

NSString *stringURL = @"appname://";
NSURL *url = [NSURL URLWithString:stringURL];
[[UIApplication sharedApplication] openURL:url];

我稍微记得有必要为Info.plist写一个值键。如何？

I slightly remember it was necessary to write a value-key to Info.plist. How?

推荐答案

将此添加到plist 。

Add this to plist .

该应用程序将由@readtext：//url

The app will by called by @"readtext://" url

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