iOS 7中的JSON解析 [英] JSON Parsing in iOS 7

问题描述

我正在为现有网站创建应用。他们目前拥有以下格式的JSON：

I am creating an app for as existing website. They currently has the JSON in the following format :

[

   {
       "id": "value",
       "array": "[{\"id\" : \"value\"} , {\"id\" : \"value\"}]"
   },
   {
       "id": "value",
       "array": "[{\"id\" : \"value\"},{\"id\" : \"value\"}]"
   } 
]

他们在使用Javascript转义\字符后解析。

which they parse after escaping the \ character using Javascript.

我的问题是当我使用iOS解析它时以下命令：

My problem is when i parse it in iOS using the following command :

NSArray *result = [NSJSONSerialization JSONObjectWithData:jsonData options:kNilOptions error:&localError];

并执行此操作：

NSArray *Array = [result valueForKey:@"array"];

而不是数组我得到了 NSMutableString object。

Instead of an Array I got NSMutableString object.

• 该网站已经投入生产，所以我不能问他们改变现有结构以返回正确的 JSON 对象。对他们来说这将是很多工作。

• The website is already in production so I just cant ask them to change their existing structure to return a proper JSON object. It would be a lot of work for them.

因此，在他们改变基础结构之前，有什么办法可以让它在<$ c中运行$ c> iOS 就像他们在网站上 javascript 一样？

So, until they change the underlying stucture, is there any way i can make it work in iOS like they do with javascript on their website?

任何帮助/建议对我都非常有帮助。

Any help/suggestion would be very helpful to me.

推荐答案

正确的JSON应该看起来像：

The correct JSON should presumably look something like:

[
    {
        "id": "value",
        "array": [{"id": "value"},{"id": "value"}]
    },
    {
        "id": "value",
        "array": [{"id": "value"},{"id": "value"}]
    }
]

但是，如果你再坚持这在你的问题中提供的格式，你需要做的字典可变用 NSJSONReadingMutableContainers ，然后调用 NSJSONSerialization 再次为每个数组条目：

But, if you're stuck this the format provided in your question, you need to make the dictionary mutable with NSJSONReadingMutableContainers and then call NSJSONSerialization again for each of those array entries:

NSMutableArray *array = [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingMutableContainers error:&error];
if (error)
    NSLog(@"JSONObjectWithData error: %@", error);

for (NSMutableDictionary *dictionary in array)
{
    NSString *arrayString = dictionary[@"array"];
    if (arrayString)
    {
        NSData *data = [arrayString dataUsingEncoding:NSUTF8StringEncoding];
        NSError *error = nil;
        dictionary[@"array"] = [NSJSONSerialization JSONObjectWithData:data options:0 error:&error];
        if (error)
            NSLog(@"JSONObjectWithData for array error: %@", error);
    }
}

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