在swift中创建一个只有两个圆角的矩形？ [英] Create a rectangle with just two rounded corners in swift?

问题描述

我需要在swift中创建一个只有两个圆角的矩形（Objective C代码也可以）。

I need to create a rectangle that have just two rounded corners in swift (Objective C code also ok).

目前我的代码正在创建两个带有矩形的矩形

At the moment my code is creating two rectangles with

CGPathCreateWithRoundedRect(CGRectMake(0, 0, 30, 60), 5, 5, nil);

和

CGPathCreateWithRoundedRect(CGRectMake(0, 0, 30, 60), 0, 0, nil);

并合并它们（有两个直角和两个圆角）但我不满意代码，我很确定应该有更好的方法来实现它。

and merging them (to have two right angle corners and two rounded ones) but I am not happy with the code and I am pretty sure there should be much better ways to do it.

我是iOS和图形开发的新手，并且很快。

I am new to iOS and graphical development and swift.

推荐答案

在 Swift 2.3 中你可以通过

let maskPath = UIBezierPath(roundedRect: anyView.bounds,
            byRoundingCorners: [.BottomLeft, .BottomRight],
            cornerRadii: CGSize(width: 10.0, height: 10.0))

let shape = CAShapeLayer()
shape.path = maskPath.CGPath
view.layer.mask = shape

---

在 Objective-C 中，您可以使用 UIBezierPath 类方法

---

In Objective-C you could use the UIBezierPath class method

bezierPathWithRoundedRect:byRoundingCorners:cornerRadii:

示例实现 -

// set the corner radius to the specified corners of the passed container
- (void)setMaskTo:(UIView*)view byRoundingCorners:(UIRectCorner)corners
{
    UIBezierPath *rounded = [UIBezierPath bezierPathWithRoundedRect:view.bounds
                                                  byRoundingCorners:corners
                                                        cornerRadii:CGSizeMake(10.0, 10.0)];
    CAShapeLayer *shape = [[CAShapeLayer alloc] init];
    [shape setPath:rounded.CGPath];
    view.layer.mask = shape;
}

并将上述方法称为 -

and call the above method as-

[self setMaskTo:anyView byRoundingCorners:UIRectCornerBottomLeft | UIRectCornerBottomRight];

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