使用块的Objective-C延迟动作 [英] Objective-C delay action with blocks

问题描述

我知道在Objective-C中有几种延迟动作的方法，如：

I know that there are several ways of delaying an action in Objective-C like:

performSelector:withObject:afterDelay:

或使用 NSTimer 。

但是有一个很棒的东西叫做积木，你可以做这样的事情：

But there is such a fancy thing called blocks where you can do something like this:

[UIView animateWithDuration:1.50 delay:0 options:(UIViewAnimationOptionCurveEaseOut|UIViewAnimationOptionBeginFromCurrentState) animations:^{

    }completion:^(BOOL finished){
}];

不幸的是，此方法仅适用于动画制作。

Unfortunately, this method applies only to animating things.

如何在一个方法中使用块创建延迟，这样我就不必使用所有 @selectors 而无需创建新的单独方法？谢谢！

How can I create a delay with a block in one method so I don't have to use all those @selectors and without the need to create a new separate method? Thanks!

推荐答案

使用dispatch_after：

use dispatch_after:

double delayInSeconds = 2.0;
dispatch_time_t popTime = dispatch_time(DISPATCH_TIME_NOW, delayInSeconds * NSEC_PER_SEC);
dispatch_after(popTime, dispatch_get_main_queue(), ^(void){
    //code to be executed on the main queue after delay
    [self doSometingWithObject:obj1 andAnotherObject:obj2];
});

这篇关于使用块的Objective-C延迟动作的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！