iOS9:canOpenURL为WhatApp的url方案返回false [英] iOS9: canOpenURL returning false for WhatApp's url scheme
问题描述
在我目前的项目中,我需要在iOS应用中分享whatsapp上的文字。
In my current project I need to share text on whatsapp from iOS app.
这是我在whatsapp上分享文字的代码: -
Here is my code to share text on whatsapp:-
NSURL *whatsappURL = [NSURL URLWithString:@"whatsapp://send?text=Hello%2C%20World!"];
if ([[UIApplication sharedApplication] canOpenURL: whatsappURL]) {
[[UIApplication sharedApplication] openURL: whatsappURL];
}
但 canOpenURL 在iOS9中始终返回false。
but canOpenURL always returning false in iOS9.
有iOS9隐私政策吗?
任何人都可以帮助我。
Is there any iOS9 privacy policy ? Can anyone help me out.
提前致谢。
推荐答案
在iOS 9中,您必须将您的应用程序想要在LSApplicationQueriesSchemes键(字符串数组)下的Info.plist中查询的任何URL方案列入白名单:
In iOS 9 you must whitelist any URL schemes your App wants to query in Info.plist under the LSApplicationQueriesSchemes key (an array of strings):
例如:
所以在你的情况下,而不是 fb
和 twitter
您必须指定 whatsapp
。
So in your case, instead of fb
and twitter
you will have to specify whatsapp
.
请注意,此机制仅适用于canOpenURL而不适用于openURL。您不需要在Info.plist中列出一个方案就可以使用openURL打开它。
希望有所帮助。
Note that this mechanism only applies to canOpenURL and not openURL. You do not need to have a scheme listed in Info.plist to be able to open it with openURL. Hope that helps.
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