二进制运算符'=='不能应用于'Any？'类型的操作数和'String'Swift iOS [英] Binary operator '==' cannot be applied to operands of type 'Any?' and 'String' Swift iOS

问题描述

我有这个 var json：[[String：Any]] = [[：]] ，其中包含JSON响应，如下所示：

I have this var json : [[String : Any]] = [[:]] which contains the JSON response as follows:

{
"id": "1",
"name": "Apple",
"category_name": "Fruits"
},
{
"id": "2",
"name": "Black shirt",
"category_name": "Fashion"
},
{
"id": "3",
"name": "iPad",
"category_name": "Gadgets"
}

我写了一个枚举：

enum : Int {
        case fruits = 0, fashion, gadgets
    }

var data = [Categories: [[String: Any]]]()

然后我有这种方法对类别进行排序：

Then I have this method to sort the categories:

func sortData() {
        data[.fruits] = self.json.filter({ $0["category_name"] == "Fruits" })
        data[.fashion] = self.json.filter({ $0["category_name"] == "Fashion" })
        data[.gadgets] = self.json.filter({ $0["category_name"] == "Gadgets" })
    }

之后我收到这样的错误

二元运算符' == '无法应用于'类型的操作数任何？'和
'字符串'

Binary operator '==' cannot be applied to operands of type 'Any?' and 'String'

请告诉我如何解决这个问题？

Please tell me how do I solve that one?

推荐答案

您应该安全地将左侧的值转换为 String ，如下所示：

You should safely cast the value on the left to String, like this:

data[.fruits] = self.json.filter({ ($0["category_name"] as? String) == "Fruits" })

这篇关于二进制运算符'=='不能应用于'Any？'类型的操作数和'String'Swift iOS的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！