iOS：让segue等待登录成功 [英] iOS: Make segue wait for login success

问题描述

我正在使用XCode 4.2的故事板功能设计iOS应用。该应用程序有一个登录屏幕，其中包含用户名和密码，并有一个登录按钮。按下登录按钮会触发另一个视图控制器的推送序列。但是，我希望seque等到登录成功后再继续下一个视图控制器。

I am designing an iOS app using XCode 4.2's storyboard feature. The app has a login screen that takes a username and password and has a button to log in. Pushing the login button triggers a push seque to another view controller. However, I want the seque to wait until the login comes back successful before proceeding to the next view controller.

我知道 prepareForSegue：sender： 但是我的问题是：登录调用是异步的。因此，我无法在那里进行登录。

I know about prepareForSegue:sender: but heres my issue: the login call is asynchronous. I therefore cannot perform the login there.

有什么可以解决这个问题吗？我可以在故事板中创建一个仅在我想要的时候触发的seque（而不是单击按钮时）？

Is there someway around this? Can I create a seque in the storyboard that is only triggered when I want it to be (as opposed to when a button is clicked)?

推荐答案

好的，我已经弄明白了。我已经将 UIButton 中的segue定义为下一个 UIViewController 。按照这种方式定义，没有办法有条件地执行segue。

Ok, I have figured it out. I had defined a segue from a UIButton to the next UIViewController. As defined in this manner, there is no way to conditionally execute the segue.

我没有把segue放在按钮上，而是从第一个<$ c c中做了一个segue $ c> UIViewController 到另一个 UIViewController 。这定义了segue，但不与它相关联。从那里我可以简单地调用 performSegueWithIdentifier：sender：当我想要执行segue时（在我的情况下是异步任务完成时）。

Instead of putting the segue on the button, I made a segue from the first UIViewController to the other UIViewController. This defines the segue, but associates no action with it. From there I can simply call performSegueWithIdentifier:sender: when I want that segue to execute (in my case being when the async task is complete).

这对我来说的主要优势在于IB维持其结构。

The main advantage of this for me is that IB maintains its structure.

非常感谢@cli_hlt指出我正确的方向（ +1）。

Big thanks to @cli_hlt for pointing me in the right direction (+1).

这篇关于iOS：让segue等待登录成功的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！