从＆QUOT取地址; canonical_addresses＆QUOT;表 [英] Fetch address from "canonical_addresses" table

问题描述

我工作的Andr​​oid应用程序。我拿来从以下URI recipient_id。

I am working on an Android application. I fetched recipient_id from the following uri.

content://mms-sms/conversations?simple=true

现在我要来从canonical_addresses 地址表使用收件人的ID，但我没有任何想法查询canonical_addresses表。我搜索了很多网站。请帮我找到解决办法的朋友。

Now I want to fetch the address from canonical_addresses" table using the recipient id. But I don't have any idea to query canonical_addresses table". I searched a lot in web. Please help me to find a solution friends.

推荐答案

规范表有两列， _id 和地址。当你的收件人ID，你做一个查找，该ID在规范的地址表。对于多个收件人ID被用空格隔开，所以你必须要拆分的结果如

Canonical table has two columns, _id and address. When you get recipient id you do a lookup for that id in the canonical addresses table. For multiple recipients the ids are separated by a space, so you'll have to split the result like

recipient_ids.split（）

和查找每个ID。

getContentResolver().query(Uri.parse("content://mms-sms/canonical-addresses"), null, "_id = " + recipientId, null, null);

或

getContentResolver().query(Uri.parse("content://mms-sms/canonical-address/" + recipientId), null, null, null, null);

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