搜索对象的NSArray以匹配任何属性的String [英] Search NSArray of objects for String matching any property

问题描述

我有一个NSArray对象，这些对象有10个属性。我想对这些对象进行文本搜索。

I have an NSArray of objects, and those objects have 10 properties. I would like to do a text search of those objects.

我知道如何一次搜索1个属性，但有一种简单的方法可以一次搜索所有属性？

I know how to search 1 property at a time, but is there an easy way to search ALL properties at once?

以下是我的对象拥有的属性列表：

Here is a list of properties that my objects have:

@property (nonatomic, retain) NSString * name;
@property (nonatomic, retain) NSString * phone;
@property (nonatomic, retain) NSString * secondaryPhone;
@property (nonatomic, retain) NSString * address;
@property (nonatomic, retain) NSString * email;
@property (nonatomic, retain) NSString * url;
@property (nonatomic, retain) NSString * category;
@property (nonatomic, retain) NSString * specialty;
@property (nonatomic, retain) NSString * notes;
@property (nonatomic, retain) NSString * guid;

如果我搜索医生，我希望看到所有结果中的一个或多个属性中有医生这个词。例如，如果1个对象的类别为doctor，而另一个对象的电子邮件地址为[e-mail]，则它们都应显示在结果中。

If I search for "doctor", I would like to see all results where 1 or more of these properties has the word "doctor" in it. For example, if 1 object has a category of "doctor", and another object has an email address of "[e-mail]", they should both show up in the results.

推荐答案

 NSString *searchTerm = @"search this";
 NSPredicate *predicate = [NSPredicate predicateWithFormat:@"SELF LIKE[cd] %@", searchTerm];
 NSArray *filtered = [array filteredArrayUsingPredicate:predicate];

如果有特定属性，您可以将谓词更改为：

If there is a specific property you can change the predicate to:

 NSPredicate *predicate = [NSPredicate predicateWithFormat:@"SELF.propertyName LIKE[cd] %@", searchTerm];

要搜索所有属性，您必须将它们与逻辑运算符绑定在一起

To search all properties, you will have to bind them together with a logical operator

  NSString *query = @"blah";
  NSPredicate *predicateName = [NSPredicate predicateWithFormat:@"name contains[cd] %@", query];
  NSPredicate *predicatePhone = [NSPredicate predicateWithFormat:@"phone contains[cd] %@", query];
  NSPredicate *predicateSecondaryPhone = [NSPredicate predicateWithFormat:@"secondaryPhone contains[cd] %@", query];
  NSArray *subPredicates = [NSArray arrayWithObjects:predicateName, predicatePhone, predicateSecondaryPhone, nil];

  NSCompoundPredicate *predicate = [NSCompoundPredicate orPredicateWithSubpredicates:subPredicates];

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