iOS按钮到uiwebview的网页 [英] iOS button to webpage with uiwebview

问题描述

对于当前项目，我将移动网站嵌入到iOS应用中。我使用了UIWebView的goback（）和goforward（）函数。但是我如何创建一个自定义函数onClick（或onTouch哪个是正确的术语）将UIWebView发送回最初加载的页面？任何帮助都会非常感激，因为到目前为止我无法在网上找到任何东西。

解决方案

添加类似于实现文件的内容：

   - （IBAction）loadPage：（id）sender; 
 {
 NSURL * url = [NSURL URLWithString：@http://www.stackoverflow.com/]; 
 NSURLRequest * request = [NSURLRequest requestWithURL：url]; 
 [webView loadRequest：request]; 
} 
  

并将其添加到头文件（每行在适当的位置）：

   - （IBAction）loadPage：（id）sender; 
 IBOutlet UIWebView * webView; 
  

然后将按钮绑定到界面构建器中的loadPage，
并将webView绑定到UIWebView。

回复评论：

我创建了这个示例项目，希望它有所帮助：

- http://dd5.org/static/iPhone_Browser_Sample.zip

绑定按钮：

右键单击并拖动到添加了上面的代码。

释放按钮。现在应该出现一个暗灰色的小面板。

然后单击该面板中的loadPage：条目。

如果代码添加正确，则该条目应该显示在那里。 / p>

For a current project I am embedding a mobile site into an iOS app. I've taken use of the goback() and goforward() functions, with UIWebView. But how would I make a custom function that onClick (or onTouch which ever is the correct term) Sends the UIWebView back to the page initially loaded? Any Help would be much appreciated as I have bene unable to find anything on the web thus far.

解决方案

Add something like to the implementation file:

- (IBAction)loadPage:(id)sender;
{
NSURL *url = [NSURL URLWithString:@"http://www.stackoverflow.com/"];
NSURLRequest *request = [NSURLRequest requestWithURL:url];
[webView loadRequest:request];
}

And add this to the header file (each line at the appropriate position):

- (IBAction)loadPage:(id)sender;
IBOutlet UIWebView *webView;

Then bind the button to loadPage within interface builder,
and bind webView to the UIWebView.

Response to comment:

I created this sample project, hopefully it helps:
- http://dd5.org/static/iPhone_Browser_Sample.zip

Binding the button:

Right-click and drag to the class where you added the code above.
Release the button. Now a little dark-gray panel should appear.
Then click on the loadPage: entry within that panel.
If the code was added correctly, the entry should show up there.

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