从ABAddressBook获取合并/统一条目 [英] Getting merged/unified entries from ABAddressBook

问题描述

我正在开发一个显示iPhone联系人的应用程序。

I'm developing an application that is showing the iPhone contacts.

ABAddressBookRef返回在iPhone联系人应用程序中只出现一次的联系人的重复条目。

The ABAddressBookRef returns duplicate entries for a contact that appears only once in the iPhone contacts application.

查看联系人卡片（来自iPhone联系人），在底部有一个名为链接联系人的部分，所以很明显苹果合并/统一这两个条目到我看到的那个。

Looking on the contact card (from the iPhone contacts), in the bottom there is a section called "Linked Contacts" so obviously apple "merge"/"unify" these two entries into the one i see.

这里的问题是模仿相同行为的最佳方法是什么，所以我的应用只显示一个条目？是否有一个API从地址簿返回合并/统一条目？

The question here is what is the best way to mimic the same behavior so my app will show only one entry? is there an API that returns the merged/unified entries from the address book?

推荐答案

创建合并的联系人列表链接的联系人：

To create a list of contacts that merges in linked contacts:

注意：ABPerson引用存储在自定义 Person 类实例中。然后将所有人存储在字典 addressBookDictionary 中，使用每个人的 recordID 作为密钥。

Note: ABPerson references are stored in custom Person class instances. All persons are then stored in a dictionary addressBookDictionary using recordID of each person as the key.

1。使用ABAddressBookCopyArrayOfAllPeople获取所有ABPersons。将人员存储在allPersonRecords数组中。

1. Get all ABPersons using ABAddressBookCopyArrayOfAllPeople. Store persons in allPersonRecords array.

2。迭代所有ABPersons。

2.1获取每个ABPerson的链接人员列表。使用

ABPersonCopyArrayOfAllLinkedPeople（ABRecordRef person）;

ABPersonCopyArrayOfAllLinkedPeople(ABRecordRef person);

如果没有链接的联系人，此方法将返回一个数组，其中包括人员引用他/她自己。因此，如果返回数组的计数> 1，则此人已链接了联系人。

If there are no linked contacts, this method will return an array including the person reference him/herself. So if the return array has a count > 1, the person has linked contacts.

2.2将链接的人添加到NSMutableSet。这些链接在将来的迭代中，人们将被跳过并且不会被处理。

2.2 Add the linked persons to a NSMutableSet. These linked persons will be skipped and not processed in future iterations.

2.3为当前的ABPerson创建一个Person实例。

2.4将链接的人员信息合并到Person实例中。链接的人可能有不同的电话号码，因此您需要将它们合并在一起。

2.4 Merge linked person information into Person instance. A linked person may have different phone numbers, so you need to merge them together.

NSArray *allPersonRecords = (NSArray *) ABAddressBookCopyArrayOfAllPeople(self.addressBook);
NSMutableSet *linkedPersonsToSkip = [[NSMutableSet alloc] init];

for (int i=0; i<[allPersonRecords count]; i++){

    ABRecordRef personRecordRef = [allPersonRecords objectAtIndex:i];

    // skip if contact has already been merged
    //
    if ([linkedPersonsToSkip containsObject:personRecordRef]) {
        continue;
    }

    // Create object representing this person
    //
    Person *thisPerson = [[Person alloc] initWithPersonRef:personRecordRef];

    // check if there are linked contacts & merge their contact information
    //
    NSArray *linked = (NSArray *) ABPersonCopyArrayOfAllLinkedPeople(personRecordRef);
    if ([linked count] > 1) {
        [linkedPersonsToSkip addObjectsFromArray:linked];

        // merge linked contact info
        for (int m = 0; m < [linked count]; m++) {
            ABRecordRef iLinkedPerson = [linked objectAtIndex:m];
            // don't merge the same contact
            if (iLinkedPerson == personRecordRef) {
                continue;
            }
            [thisPerson mergeInfoFromPersonRef:iLinkedPerson];
        }
    }
    [self.addressBookDictionary setObject:thisPerson forKey:thisPerson.recordID];
    [thisPerson release];
    [linked release];
}
[linkedPersonsToSkip release];
[allPersonRecords release];

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