如何将MaxDate和MinDate设置为从ios上的webservice返回的DatePicker [英] how to set MaxDate and MinDate to DatePicker returned from webservice on ios

问题描述

我有一个XML响应，它返回以下数据作为回复

I have a an XML response which returns the below data as response

Start Day of the Week-Wednesday
End Day of the Week-Sunday
Start time -16:00
End time -19:00

现在我知道如何解析这些值，但是我对如何将这些值设置为日期选择器的MaxDate和MinDate感到困惑，因为返回的响应总是不一样，可能会在以后更改，我的意思是后来的一周开始，一周的结束日可能会改变，所以如何实现它以便它会有效...请帮助我的朋友..我尝试了一些代码，但我不确定我是否在正确的道路上，所以请告诉我方向并帮助我

Now I know how to parse these values ,but I am getting confused on how can I set these values to MaxDate and MinDate of the Date Picker,because the returned response is not same always and may change later,I mean later start day of the week ,end day of the week may change,so how shall I implement it so that it will be efficient..please help me friends..I tried some code which is below,but I am not sure whether i am on the right path,so please show me direction and help me out

NSDate *today = [NSDate date];
NSCalendar *gregorian = [[NSCalendar alloc]
                         initWithCalendarIdentifier:NSGregorianCalendar];

[Gregorian setfirstDayofWeek:2];
NSDateComponents  * comps =[[NSDateComponents alloc]init];
[comps setday:7];

推荐答案

所以我建议你创建两个 UIDatePicker 或一个自定义 UIDatePicker 。

So I suggest you to create two UIDatePicker's or one custom UIDatePicker.

如果您先选择方法，您可以按以下方式在 UIDatePicker 中设置时间范围：

If you will select first approach, you can set ranges of time in UIDatePicker in following way:

使用IB：

1. 选择日期选择器。


2. 打开实用程序 - >属性检查器


3. 块约束：


4. 选择最短日期并设置其值 01/01/1970 16:00:00


5. 选择最大日期并设置其值 01/01/1970 19:00:00


6. 设定值日期至 01/01/1970 16:00:00

1. Select your Date picker.
2. Open Utilities -> Attribute inspector
3. In block Constraints :
4. Select Minimum Date and set its value 01/01/1970 16:00:00
5. Select Maximum Date and set its value 01/01/1970 19:00:00
6. Set value Date to 01/01/1970 16:00:00

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