如何从常规UIFont创建粗体UIFont？ [英] How do I create a bold UIFont from a regular UIFont?

问题描述

如果我有一个 UIFont 对象，是否可以将其转换为粗体？我不知道字体名称，我只有一个UIFont对象。我想要的是一个函数，如

If I have a UIFont object, is it possible to convert it to bold? I don't know the font name, I just have a UIFont object. What I want is a function like

UIFont *boldFontFromFont(UIFont *input)
{
    return [input derivedFontWithFontWeight:UIFontWeightBold];
}

如何更改代码以使其正常工作。 （上面的代码不起作用，我只是说明了这一点。）

How can I change the code so that it works. (The code above does not work, I just made it up to illustrate the point.)

提前致谢。

推荐答案

要获得粗体字体，您需要从字体系列中传递字体的特定名称。您可以从给定字体中获取字体系列名称，然后列出此系列中的所有字体。通常，粗体字体的名称中将包含粗体，但格式不严格，例如可能存在Helvetica-BoldOblique等变体。你可以从这段代码开始：

To get a bold font you need to pass a specific name of the font from a font family. You can get a font family name from a given font, then list all fonts from this family. In general, a bold font will contain "bold" in its name, but the format isn't strict and there could be variations like "Helvetica-BoldOblique", for example. You can start from this code:

- (UIFont *)boldFontFromFont:(UIFont *)font
{
    NSString *familyName = [font familyName];
    NSArray *fontNames = [UIFont fontNamesForFamilyName:familyName];
    for (NSString *fontName in fontNames)
    {
        if ([fontName rangeOfString:@"bold" options:NSCaseInsensitiveSearch].location != NSNotFound)
        {
            UIFont *boldFont = [UIFont fontWithName:fontName size:font.pointSize];
            return boldFont;
        }
    }
    return nil;
}

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