NSString问题 - rangeOfString方法 [英] NSString question - rangeOfString method

问题描述

我遇到了一个我无法弄清楚的问题。

I am having an issue that I can't figure out.

我正在尝试对字符串运行rangeOfString方法，我不确定如何确定是否找不到该字符串。例如：

I'm trying to run the rangeOfString method on a string, and I'm not sure how to determine if the string was not found. For example:

NSRange range = [@"abc" rangeOfString:@"d" options:NSCaseInsensitiveSearch range:NSMakeRange(0,3)];

显然，d不包含在字符串abc中。我希望能够这样做：

Clearly, "d" is not contained in the string "abc." I'd like to be able to do this:

if(the range is empty since "d" is not in "abc")
   //do something

这是什么代码？

谢谢！

推荐答案

来自的文档NSString

-[NSString rangeOfString]

返回值

Return Value

NSRange结构给出
的位置和长度
的接收者第一次出现aString。
如果aString未找到
或为空（@），则返回 {NSNotFound，0} 。

An NSRange structure giving the location and length in the receiver of the first occurrence of aString. Returns {NSNotFound, 0} if aString is not found or is empty (@"").

所以看起来像：

if ([@"abc" rangeOfString:@"d"].location == NSNotFound){
  //Do something

Apple批准了吗方式。

Is the Apple-approved way.

编辑：

我做了一个非常糟糕的拼写错误，修好了它，谢谢Kalle。

I made a really bad typo, fixed it, thanks Kalle.

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