如何使用UIButton作为切换按钮？ [英] How to use UIButton as Toggle Button?

问题描述

我正在尝试为表格中的每个单元格创建一个切换按钮。按下时，它将改变图像，再次按下时，它将再次改变图像 - 切换。

I am trying to create a toggle button for each cell in my table. When pressed, it will change the image and when pressed again it will change the image again -- Toggle.

在 UIButton 类中，我没有看到选择 状态。

In the UIButton class I don't see a selected state.

我正在寻找一种使用UIButton创建切换按钮的方法，这样我就可以在每次点击时更改状态。

I'm looking for a way to create a toggle button with UIButton so that I can change the state on each click.

我现在正在使用 rmq ruby​​motion 进行此操作

This is how I'm doing it in rubymotion right now using rmq

@fav_button.on(:touch) do |sender|
  puts "pressed fav button for id: " + data[:id] + " and name: " + data[:name]
  #how do I change the state here?
end

推荐答案

您可以轻松创建切换按钮，您只需要为各个状态设置相应的图像，之后，您可以使用选择的属性在这些图像之间切换。

You can create toggle button easily, you just need to set respective images for respective states, after that, you can use the selected property to toggle between these images.

我制作了一个纯粹的Objective-c代码来展示你如何做到这一点，但你也可以在Storyboards ou Xibs中设置图像，结账：

I made a pure objective-c code to show how you can do that, but you can set the images anyway in Storyboards ou Xibs too, check out:

// First, set the images for normal state and selected state
[button setImage:normalImage forState:UIControlStateNormal];
[button setImage:selectedImage forState:UIControlStateSelected];

// Don't forget to add an action handler to toggle the selected property
[button addTarget:self action:@selector(buttonTouch:withEvent:) forControlEvents:UIControlEventTouchUpInside];

// Now, in your button action handler, you can do something like this:
- (void)buttonTouch:(UIButton *)aButton withEvent:(UIEvent *)event
{
  aButton.selected = !aButton.selected;
}

我希望这可以帮到你。

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