使用标识符启动iPhone应用程序 [英] Launch iPhone Application with Identifier

问题描述

我正在尝试在我的应用程序中启动应用程序。

例如：如果我在testApp1中按下一个按钮，它应该打开testApp2。

有没有用App Identifier做到这一点的方法??

I'm trying to Launch an application within my App.
For example: If I press a Button in my testApp1, it should Open up testApp2.
Is there any Way to do this with the App Identifier??

我听说过一个名为 launchApplicationWithIdentifier：suspend：的无证方法，但这对我不起作用，或者我错了。

我试过这个：

[UIApplication launchApplicationWithIdentifier：@com.test.testApp2暂停：否]

但它不起作用。

I heard something about a undocumented method called launchApplicationWithIdentifier: suspend: but that doesn't work for me, or i'm using it wrong.
I tried this:
[UIApplication launchApplicationWithIdentifier:@"com.test.testApp2" suspend:NO]
But it didn't work.

推荐答案

更好地使用 [[UIApplication sharedApplication] openUrl：] 。您需要在第二个应用程序中为此设置自定义URL方案。查看本教程或简单使用iphone自定义URL方案进行搜索。有很多很好的教程。

Better use [[UIApplication sharedApplication] openUrl:]. You'll need set a custom URL scheme in your second app for that. Check this tutorial or simply do a search with "iphone custom URL schemes". There's a lot of good tutorials.

这篇关于使用标识符启动iPhone应用程序的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！