在NSArray中获取NSDictionary中的所有值 [英] Grab all values in NSDictionary inside an NSArray

问题描述

我有一个充满NSDictionary对象的NSArray，每个NSDictionary里面都有一个唯一的ID。我想根据ID查找特定词典，并在我自己的词典中获取该词典的所有信息。

myArray包含：

  [index 0] myDictionary对象
 name = apple，
 weight = 1 pound，
 number = 294，
 
 [index 1] myDictionary对象
 name = pear，
 weight = .5 pound，
 number = 149，
 
 [index 3 ] myDictionary对象（等等......）
  

我想得到第二本字典的名称和重量object（我不知道对象的索引...如果只有两个dicts，我可以从 [myArray objectAtIndex：1] 中创建一个字典<） / p>

所以，我知道数字149.我怎样才能将myArray中的第二个myDictionary对象变成新的NSDictionary？

解决方案

作为雅各布答案的替代方案，你也可以让字典找到对象： / p>

  NSPredicate * finder = [NSPredicate predicateWithFormat：@number = 149]; 
 NSDictionary * targetDictionary = [[array filteredArrayUsingPredicate：finder] lastObject]; 
  

I have an NSArray full of NSDictionary objects, and each NSDictionary has a unique ID inside. I want to do lookups of particular dictionaries based on the ID, and get all the information for that dictionary in my own dictionary.

myArray contains:

[index 0] myDictionary object
  name = apple,
  weight = 1 pound,
  number = 294,

[index 1] myDictionary object
  name = pear,
  weight = .5 pound,
  number = 149,

[index 3] myDictionary object (etc...)

I want to get the name and weight for the second dictionary object (I won't know the index of the object... if there were only two dicts, I could just make a dictionary from [myArray objectAtIndex:1])

So, say I know the number 149. How would I be able to get the second myDictionary object out of myArray into a new NSDictionary?

解决方案

As an alternative to Jacob's answer, you could also just ask the dictionary to find the object:

NSPredicate *finder = [NSPredicate predicateWithFormat:@"number = 149"];
NSDictionary *targetDictionary = [[array filteredArrayUsingPredicate:finder] lastObject];

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