如何迭代此json结构以生成另一个结构? [英] How do I iterate over this json structure to produce another structure?
问题描述
我有这个json结构。
I have this json structure.
x=[{
"value": 1.37,
"date_transacted": "2015-01-01"
}]
来自这个json结构,我想生成以下json结构;
From this json structure, I want to produce the following json structure;
y1=[{
c: [{
v: "2015-01-01"
},
{
v: "1.37"
}]
}]
我已经编写了代码来执行此操作。它看起来像这样;
I have written the code to do this. It looks like this;
var y1 = [{ c:[ {"v":x[0].value}, {"v":x[0].date_transacted} ] }];
我的问题来自 x
有几个json键/值对。看起来像这样的东西;
My problem comes when x
has several json key/value pairs. Something that look like this;
x=[{
"value": 1.37,
"date_transacted": "2015-01-01"
},
{
"value": 1.62,
"date_transacted": "2015-02-01"
},
{
"value": 1.83,
"date_transacted": "2015-03-01"
}]
通过对象数组迭代我的代码以产生所需的json结构的有效方法是什么?
What is an effective way to iterate my code through the array of objects to produce the desired json structure which should look like this?
y=[{
c: [{
v: "2015-01-01"
},
{
v: "1.37"
}]
},
{
c: [{
v: "2015-01-02"
},
{
v: "1.62"
}]
},
{
c: [{
v: "2015-01-03"
},
{
v: "1.83"
}]
}]
推荐答案
此处的其他答案(@ user2415266除外)不是动态的,硬编码接受确切的输入,并不是特别可重复使用。如果您有超过2个属性,或者在@ Siguza的情况下,如果您的属性不是'date_transacted'和'value',它们将会失败。
The other answers here (except @user2415266) are not dynamic, hard-coded to accept an exact input, and are not particularly reusable. They will fail if you have more than 2 properties, or in @Siguza's case, also if you have properties not called 'date_transacted' and 'value'.
function restructureJson(obj) {
var output = {c:[]};
for (var i in obj) {
output.c.push({v:obj[i]});
}
return output;
}
此函数可在任何大小的任何对象数组中重复使用,包含任何物业数量。
This function is reusable on any array of objects, of any size, containing any number of properties.
// Simple example
var json1 = [{
"value": 1.37,
"date_transacted": "2015-01-01"
}];
// More complex
var json2 = [{
"value": 1.37,
"date_transacted": "2015-01-01",
"another_value": "test",
"more": "12356"
},
{
"value": 1.62
},
{
"value": 1.83,
"date_transacted": "2015-03-01",
"stuff": "124334654567"
}];
// Map the function to the arrays
a = json1.map(restructureJson);
b = json2.map(restructureJson);
这篇关于如何迭代此json结构以生成另一个结构?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!