使用jackson将xml转换为json [英] Converting xml to json using jackson
问题描述
我想将xml转换为json。
I want to convert an xml to json.
xml的格式如下 -
The format of of xml is as follows -
<default>
<column>
<title>Title 1</title>
<id>id1</id>
<value>val1</value>
</column>
<column>
<title>Title 2</title>
<id>id2</id>
<value>val2</value>
</column>
<column>
<title>Title 3</title>
<id>id3</id>
<value>val3</value>
</column>
</default>
转换后我期待跟随json -
And after the conversion i am expecting following json -
{
"column": [
{
"title": "Title 1",
"id": "id1",
"value": "val1"
},
{
"title": "Title 2",
"id": "id2",
"value": "val2"
},
{
"title": "Title 3",
"id": "id3",
"value": "val3"
}
]
}
<但是,当我为此目的使用杰克逊时,它让我跟随json -
But when i use jackson for this purpose it gives me following json -
{
"column": {
"title": "Title 3",
"id": "id3",
"value": "val3"
}
}
我尝试过使用jackson 1.9和jackson 2.1,但它并没有给我预期的输出。
I have tried using jackson 1.9 and jackson 2.1, but it didnt gave me the expected output.
有人可以告诉我,不管我是可能的还是我需要更改我的xml格式?
以下是我为实现上述情况而编写的代码 -
Can some one please let me know that whether it is possible or i need to change my xml format ? Following is the code that i have written to acheive the above scenario -
try {
XmlMapper xmlMapper = new XmlMapper();
Map entries = xmlMapper.readValue(new File("xmlPath"), Map.class);
ObjectMapper jsonMapper = new ObjectMapper();
String json = jsonMapper.writeValueAsString(entries);
System.out.println(json);
} catch (Exception e) {
e.printStackTrace();
}
谢谢
推荐答案
我能够通过使用 org.json API将源XML转换为 JSONObject 然后由Jackson API发送给JSON。
I was able to get the solution to this problem by using org.json API to convert source XML to JSONObject and then to JSON by Jackson API.
代码
import java.io.File;
import java.io.FileInputStream;
import java.io.InputStream;
import org.apache.commons.io.IOUtils;
import org.json.JSONObject;
import org.json.XML;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.databind.SerializationFeature;
...
...
try (InputStream inputStream = new FileInputStream(new File(
"source.xml"))) {
String xml = IOUtils.toString(inputStream);
JSONObject jObject = XML.toJSONObject(xml);
ObjectMapper mapper = new ObjectMapper();
mapper.enable(SerializationFeature.INDENT_OUTPUT);
Object json = mapper.readValue(jObject.toString(), Object.class);
String output = mapper.writeValueAsString(json);
System.out.println(output);
}
...
...
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