如何在REST中创建POST请求以接受JSON输入? [英] How to create a POST request in REST to accept a JSON input?
问题描述
我正在尝试学习RESTful Web服务。我正在创建一组简单的Web服务。我开始处理POST时卡住了。
I am trying to learn RESTful web services. And am creating a simple set of web services. Got stuck when I started working on POST.
我想将JSON输入传递给POST方法。这就是我在代码中所做的:
I want to pass JSON input to a POST method. This is what I did in the code:
@RequestMapping(value = "/create", method = RequestMethod.POST, consumes="application/x-www-form-urlencoded", produces="text/plain")
@ResponseStatus(HttpStatus.CREATED)
public @ResponseBody String createChangeRequest(MyCls mycls) {
return "YAHOOOO!!";
}
我在我的POM.xml中包含了Jackson。
I included Jackson in my POM.xml.
<dependency>
<groupId>org.codehaus.jackson</groupId>
<artifactId>jackson-mapper-lgpl</artifactId>
<version>1.9.13</version>
</dependency>
MyCls是一个简单的类,有几个getter和setter。
MyCls is a simple class with a few getters and setters.
我从chrome的简单REST客户端调用上面的POST服务。
I am calling the above POST service from chrome's simple REST client.
URL: http://localhost:8080/MYWS/cls/create
Data: {<valid-json which corresponds to each variable in the MyCls pojo}
我看到以下回复:
415 Unsupported Media Type
The server refused this request because the request entity is in a format not supported by the requested resource for the requested method.
我尝试在REST客户端的POST请求中添加标题为application / json - 但是没有帮助。
I tried adding header as "application/json" in the POST request in the REST client - but that did not help.
有人能让我知道我在这里缺少什么吗?如何自动将输入JSON映射到MyCls pojo?我在这里错过了任何配置吗?
Can someone let me know what I am missing here? How can I automatically map my input JSON to the MyCls pojo? Am I missing any configuration here?
编辑:
MyCls.java
MyCls.java
public class MyCls{
private String name;
private String email;
private String address;
public String getName() {
return name;
}
public void setName(String name) {
name= name;
}
---similar getter and setter for email, address--
}
$来自chrome简单REST客户端的b $ b
json:
json from chrome Simple REST Client:
{"name":"abc", "email":"de@test","address":"my address"}
编辑:
将我的控制器方法更改为以下内容,但仍然看到相同的错误:
Changed my controller method to the following, but still see the same error:
@RequestMapping(value = "/create", method = RequestMethod.POST, consumes="application/json", produces="text/plain")
@ResponseStatus(HttpStatus.CREATED)
public @ResponseBody String createChangeRequest(@RequestBody MyCls mycls) {
return "YAHOOOO!!";
}
推荐答案
假设您的客户正在发送 application / json
作为其内容类型,然后处理程序映射到
Assuming your client is sending application/json
as its content type, then a handler mapped to
consumes="application/x-www-form-urlencoded"
将无法处理它。实际的内容类型
与预期的不匹配。
will not be able to handle it. The actual Content-type
doesn't match the expected.
如果你期望 application / json
,你应该
consumes="application/json"
另外,声明
public @ResponseBody String createChangeRequest(MyCls mycls) {
是(在默认环境中)相当于
is (in default environment) equivalent to
public @ResponseBody String createChangeRequest(@ModelAttribute MyCls mycls) {
这意味着 MyCls
object是从请求参数创建的,而不是从JSON主体创建的。相反,你应该
This means the MyCls
object is created from request parameters, not from JSON body. Instead, you should have
public @ResponseBody String createChangeRequest(@RequestBody MyCls mycls) {
以便Spring将您的JSON反序列化为 MyCls
类型的对象。
so that Spring deserializes your JSON to an object of type MyCls
.
这篇关于如何在REST中创建POST请求以接受JSON输入?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!