杰克逊序列化忽略时区 [英] Jackson Serialization Ignore Timezone
本文介绍了杰克逊序列化忽略时区的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我使用以下代码序列化从外部服务获取的响应,并返回作为我服务的一部分的json响应。但是,当外部服务返回时间值和时区(10:30:00.000-05.00)时,杰克逊将其转换为15:30:00。如何忽略时区值?
I use the below code for serializing the response that get from an external service an return a json response back as part of my service. However when the external service return a time value along with timezone (10:30:00.000-05.00) , jackson is converting it to 15:30:00. How can I ignore the timezone value?
public interface DateFormatMixin {
@JsonFormat(shape=JsonFormat.Shape.STRING, pattern="HH:mm:ss")
public XMLGregorianCalendar getStartTime();
@JsonFormat(shape=JsonFormat.Shape.STRING, pattern="HH:mm:ss")
public XMLGregorianCalendar getEndTime();
}
public ObjectMapper objectMapper() {
com.fasterxml.jackson.databind.ObjectMapper responseMapper = new com.fasterxml.jackson.databind.ObjectMapper();
responseMapper.addMixIn(Time.class, DateFormatMixin.class);
return responseMapper;
}
推荐答案
您可以创建自定义反序列化器
You can create custom deserializer
public class CustomJsonTimeDeserializerWithoutTimeZone extends JsonDeserializer<Time>{
@Override
public Time deserialize(JsonParser jp, DeserializationContext ctxt)
throws IOException, JsonProcessingException {
DateFormat format = new SimpleDateFormat("hh:mm:ss.SSS");
Time time = null;
try{
Date dt = format.parse("10:30:00.000-05.00".substring(0,12)); // remove incorrect timezone format
return new Time(dt.getTime());
}catch (ParseException e){
e.printStackTrace();
}
}
}
告诉杰克逊使用自定义反序列化器
tell jackson to use your custom deserializer
public class Model{
@JsonDeserialize(using = CustomJsonTimeDeserializerWithoutTimeZone.class)
private Time time;
}
并像这样使用:
ObjectMapper mapper = new ObjectMapper();
String jsonString = ...// jsonString retrieve from external service
Model model = mapper.readValue(jsonString, Model.class);
您可以使用Jackson Custom Serialization为您的服务回复添加时区信息
You can use Jackson Custom Serialization to add timezone information for your service response
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