反序列化“祖鲁语”在杰克逊的ISO8601格式的时间 [英] Deserialize "Zulu" time in ISO8601 format in jackson

问题描述

我需要使用Jackson将格式时间 2016-11-28T10：34：25.097Z 反序列化为Java8的ZonedDateTime。

I have a need to de-serialize time of format 2016-11-28T10:34:25.097Z using Jackson into ZonedDateTime of Java8.

我相信我正确配置了ObjectMapper（工厂方法）：

I believe I correctly configured ObjectMapper (a factory method):

 @Bean
ObjectMapper getObjectMapper() {
    ObjectMapper objectMapper = new ObjectMapper();
    // some other config...
    objectMapper.registerModule(new JavaTimeModule());
    return objectMapper;
}

我在DTO的代码中有一个字段

And I have in my code for DTO a field

  @JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "yyyy-MM-dd'T'HH:mm:ss.SSSZ")
private ZonedDateTime updatedAt;

当我尝试解析杰克逊时，我得到了

when I try to parse this by Jackson, I get

 java.lang.IllegalArgumentException: Can not deserialize value of type java.time.ZonedDateTime 
 from String "2016-11-28T10:34:25.097Z": Text '2016-11-28T10:34:25.097Z' could not be parsed,
 unparsed text found at index 23  at [Source: N/A; line: -1, column: -1]  

没有@JsonFormat问题仍然存在。

Without @JsonFormat problem remains.

我怎么可能克服这个？

推荐答案

问题可能在于'Z'在模式中。它不允许在日期时间值中使用文字Z。请尝试'X'。

The problem is probably with 'Z' in the pattern. It does not allow literal 'Z' in the date time value. Try 'X' instead.

  @JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "yyyy-MM-dd'T'HH:mm:ss.SSSX")

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