将JarEntry转换为File [英] Convert JarEntry to File
问题描述
我正在使用一个想要File()作为参数的库。
I'm using a library which wants a File() as an argument.
我要传递的文件是我要用我的app打包的文件,作为.jar的一部分
The file I want to pass it is one I want to package with my app, as part of the .jar
有没有办法将我从.jar中获取的JarEntry转换为我可以传递的File对象?
Is there any way to convert the JarEntry that I get from within my .jar to a File object I can pass?
如果没有,我必须暂时将资源复制到磁盘,哪里是放置临时文件的最佳位置?
If not and I have to copy the resource to disk temporarily, where's the best place to put the temporary file?
谢谢。
推荐答案
您无法获取JARFile中的文件路径,只能获取流,因此您应该将其提取到临时目录,然后传递该提取的文件。
这是我写的一个函数,当我之前提供带有jar的数据库时。
You cannot get a path to a file within a JARFile, only a stream, so you should extract it to the temporary directory and then pass that extracted file. Here's a function I wrote to do this when I provided a db with a jar previously.
/**
* This method is responsible for extracting resource files from within the .jar to the temporary directory.
* @param filePath The filepath relative to the 'Resources/' directory within the .jar from which to extract the file.
* @return A file object to the extracted file
**/
public File extract(String filePath)
{
try
{
File f = File.createTempFile(filePath, null);
FileOutputStream resourceOS = new FileOutputStream(f);
byte[] byteArray = new byte[1024];
int i;
InputStream classIS = getClass().getClassLoader().getResourceAsStream("Resources/"+filePath);
//While the input stream has bytes
while ((i = classIS.read(byteArray)) > 0)
{
//Write the bytes to the output stream
resourceOS.write(byteArray, 0, i);
}
//Close streams to prevent errors
classIS.close();
resourceOS.close();
return f;
}
catch (Exception e)
{
System.out.println("An error has occurred while extracting the database. This may mean the program is unable to have any database interaction, please contact the developer.\nError Description:\n"+e.getMessage());
return null;
}
}
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