如何大写字符串中每个单词的第一个字符 [英] How to capitalize the first character of each word in a string

问题描述

是否有一个内置于Java中的函数可以将字符串中每个单词的第一个字符大写，并且不会影响其他字符？

Is there a function built into Java that capitalizes the first character of each word in a String, and does not affect the others?

示例：

• jon skeet - > Jon Skeet


• miles o'Brien - > Miles O'Brien （B仍然存在资本，这排除标题案例）


• 旧麦克唐纳 - > 旧麦当劳 *

• jon skeet -> Jon Skeet
• miles o'Brien -> Miles O'Brien (B remains capital, this rules out Title Case)
• old mcdonald -> Old Mcdonald*

*（ Old McDonald 也会找到，但我不喜欢不要期望它那么聪明。）

*(Old McDonald would be find too, but I don't expect it to be THAT smart.)

快速浏览 Java字符串文档仅显示 toUpperCase（）和 toLowerCase（），这当然不能提供所需的行为。当然，谷歌的结果由这两个功能主导。它看起来像一个必须已经发明的轮子，所以它可以毫无伤害，所以我可以在将来使用它。

A quick look at the Java String Documentation reveals only toUpperCase() and toLowerCase(), which of course do not provide the desired behavior. Naturally, Google results are dominated by those two functions. It seems like a wheel that must have been invented already, so it couldn't hurt to ask so I can use it in the future.

推荐答案

WordUtils.capitalize（str） （来自 apache commons-text ）

（注：如果您需要fOO BAr成为Foo Bar，请使用 capitalizeFully（ ..）代替）

(Note: if you need "fOO BAr" to become "Foo Bar", then use capitalizeFully(..) instead)

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