正则表达式用于排除特殊字符 [英] Regular expression for excluding special characters

问题描述

我无法想出一个正则表达式，它基本上会将某些特殊字符列入黑名单。

I am having trouble coming up with a regular expression which would essentially black list certain special characters.

我需要使用它来验证输入字段中的数据（在一个Java Web应用程序）。我们希望允许用户输入任何数字，字母（我们需要包括重音字符，例如法语或德语）和一些特殊字符，例如' - 。等等。

I need to use this to validate data in input fields (in a Java Web app). We want to allow users to enter any digit, letter (we need to include accented characters, ex. french or german) and some special characters such as '-. etc.

如何将<>％$等字符列入黑名单？

How do I blacklist characters such as <>%$ etc?

任何帮助都将是非常感激。

Any help would be greatly appreciated.

推荐答案

我只是将字符列入白名单。

I would just white list the characters.

^[a-zA-Z0-9äöüÄÖÜ]*$

建立一个黑名单与正则表达式同样简单，但你可能需要添加更多的字符 - 在unicode中有很多中文符号...;）

Building a black list is equally simple with regex but you might need to add much more characters - there are a lot of Chinese symbols in unicode ... ;)

^[^<>%$]*$

表达式[^ （这里有很多字符）]只匹配未列出的任何字符。

The expression [^(many characters here)] just matches any character that is not listed.

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