如何从java中的URL读取XML响应？ [英] How to read XML response from a URL in java?

问题描述

我需要编写一个简单的函数来获取URL并处理XML或JSON的响应，我已经检查了Sun网站 https://swingx-ws.dev.java.net/servlets/ProjectDocumentList ，但是无处可找到HttpRequest对象，是否可以在Java中执行此操作？我正在编写一个富客户端应用程序。

I need to write a simple function that takes a URL and processes the response which is XML or JSON, I have checked the Sun website https://swingx-ws.dev.java.net/servlets/ProjectDocumentList , but the HttpRequest object is to be found nowhere, is it possible to do this in Java? I`m writting a rich client end app.

推荐答案

对于输入流的xml解析，你可以这样做：

For xml parsing of an inputstream you can do:

// the SAX way:
XMLReader myReader = XMLReaderFactory.createXMLReader();
myReader.setContentHandler(handler);
myReader.parse(new InputSource(new URL(url).openStream()));

// or if you prefer DOM:
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(new URL(url).openStream());

但是要通过http从服务器到客户端进行通信我更喜欢使用粗野图书馆或spring http invoker lib

But to communicate over http from server to client I prefer using hessian library or springs http invoker lib

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