在JAR中加载属性文件？ [英] Load properties file in JAR?

问题描述

当我的网络应用程序所依赖的其中一个jar试图从jar中加载属性文件时，我遇到了麻烦。这是jar中的代码。

I'm having trouble when one of the jars that my web app depends on tries to load a properties file from within the jar. Here is the code in the jar.

static
{
    Properties props = new Properties();
    try 
    {
        props.load(ClassLoader.getSystemResourceAsStream("someProps.properties"));
    } catch (IOException e) 
    {
        e.printStackTrace();
    }
    someProperty = props.getProperty("someKey");
}

属性文件位于我的src / main / resources目录中Maven项目。当我从Eclipse中的junit测试运行此代码时，它执行得很好。当项目使用Maven构建到jar中，并作为依赖项包含在我的Web应用程序中时，它无法找到属性文件。我知道属性文件位于依赖于jar的基本目录中，我不知道如何解决这个问题。

The properties file is in my "src/main/resources" directory of the Maven project. When I run this code from my junit test in Eclipse, it executes just fine. When the project is built with Maven into a jar, and included as a dependency in my web app, it fails to locate the properties file. I know that the properties file is at the base directory of the depended on jar, I don't know how to fix this.

推荐答案

<问题是你正在使用 getSystemResourceAsStream 。使用简单的 getResourceAsStream 。系统资源从系统类加载器加载，几乎可以肯定不是你的jar作为webapp运行时加载到的类加载器。

The problem is that you are using getSystemResourceAsStream. Use simply getResourceAsStream. System resources load from the system classloader, which is almost certainly not the class loader that your jar is loaded into when run as a webapp.

它在Eclipse中有效，因为在启动应用程序时，系统类加载器配置了jar作为其类路径的一部分。 （例如，java -jar my.jar将在系统类加载器中加载my.jar。）Web应用程序不是这种情况 - 应用程序服务器使用复杂的类加载将Web应用程序彼此隔离，并与应用程序服务器的内部隔离。例如，请参阅 tomcat classloader how-to ，以及使用的类加载器层次结构图。

It works in Eclipse because when launching an application, the system classloader is configured with your jar as part of its classpath. (E.g. java -jar my.jar will load my.jar in the system class loader.) This is not the case with web applications - application servers use complex class loading to isolate webapplications from each other and from the internals of the application server. For example, see the tomcat classloader how-to, and the diagram of the classloader hierarchy used.

编辑：通常，你会调用 getClass（）。getResourceAsStream（）在类路径中检索资源，但是当您在静态初始化程序中获取资源时，您需要显式命名要加载的类加载器中的类。最简单的方法是使用包含静态初始化程序的类，
例如

Normally, you would call getClass().getResourceAsStream() to retrieve a resource in the classpath, but as you are fetching the resource in a static initializer, you will need to explicitly name a class that is in the classloader you want to load from. The simplest approach is to use the class containing the static initializer, e.g.

[public] class MyClass {
  static
  {
    ...
    props.load(MyClass.class.getResourceAsStream("/someProps.properties"));
  }
}

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