以编程方式关闭JOptionPane [英] Closing A JOptionPane Programmatically

问题描述

我正在开发一个项目，我希望以编程方式关闭通用的JOptionPane（通过不点击任何按钮）。当计时器到期时，我想关闭任何可能打开的可能的JOptionPane并将用户踢回我的程序的登录屏幕。我可以很好地踢回用户，但除非我实际点击它上面的按钮，否则JOptionPane仍然存在。

I am working on a project in which I would like to close a generic JOptionPane programmatically (by not physically clicking on any buttons). When a timer expires, I would like to close any possible JOptionPane that may be open and kick the user back to the login screen of my program. I can kick the user back just fine, but the JOptionPane remains unless I physically click a button on it.

我看过许多没有运气的网站。似乎不可能在JOptionPane的Red X上调用doClick（）方法，并且使用JOptionpane.getRootFrame（）。dispose（）不起作用。

I have looked on many sites with no such luck. A doClick() method call on the "Red X" of the JOptionPane does not seem possible, and using JOptionpane.getRootFrame().dispose() does not work.

推荐答案

从技术上讲，你可以循环遍历应用程序的所有窗口，检查它们是否为JDialog类型并且有一个JOptionPane类型的子节点，如果是这样，则处理对话框：

Technically, you can loop through all windows of the application, check is they are of type JDialog and have a child of type JOptionPane, and dispose the dialog if so:

Action showOptionPane = new AbstractAction("show me pane!") {

    @Override
    public void actionPerformed(ActionEvent e) {
        createCloseTimer(3).start();
        JOptionPane.showMessageDialog((Component) e.getSource(), "nothing to do!");
    }

    private Timer createCloseTimer(int seconds) {
        ActionListener close = new ActionListener() {

            @Override
            public void actionPerformed(ActionEvent e) {
                Window[] windows = Window.getWindows();
                for (Window window : windows) {
                    if (window instanceof JDialog) {
                        JDialog dialog = (JDialog) window;
                        if (dialog.getContentPane().getComponentCount() == 1
                            && dialog.getContentPane().getComponent(0) instanceof JOptionPane){
                            dialog.dispose();
                        }
                    }
                }

            }

        };
        Timer t = new Timer(seconds * 1000, close);
        t.setRepeats(false);
        return t;
    }
};

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