从127.0.0.1到2130706433，然后再回来 [英] Going from 127.0.0.1 to 2130706433, and back again

问题描述

使用标准Java库，从IPV4地址（127.0.0.1）的虚线字符串表示到等效整数的最快方法是什么？表示（ 2130706433 ）。

Using the standard Java libraries, what is the quickest way to get from the dotted string representation of an IPV4-address ("127.0.0.1") to the equivalent integer representation (2130706433).

相应地，反转所述操作的最快方法是什么 - 从整数开始 2130706433 到字符串表示127.0.0.1？

And correspondingly, what is the quickest way to invert said operation - going from the integer 2130706433 to the string representation"127.0.0.1"?

推荐答案

String to int：

String to int:

int pack(byte[] bytes) {
  int val = 0;
  for (int i = 0; i < bytes.length; i++) {
    val <<= 8;
    val |= bytes[i] & 0xff;
  }
  return val;
}

pack(InetAddress.getByName(dottedString).getAddress());

Int to string：

Int to string:

byte[] unpack(int bytes) {
  return new byte[] {
    (byte)((bytes >>> 24) & 0xff),
    (byte)((bytes >>> 16) & 0xff),
    (byte)((bytes >>>  8) & 0xff),
    (byte)((bytes       ) & 0xff)
  };
}


InetAddress.getByAddress(unpack(packedBytes)).getHostAddress()

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