JSON日期到Java日期? [英] JSON date to Java date?
问题描述
我无处可寻。我从返回标准JSON日期的API中获取一些JSON。您可以通过在JavaScript控制台中运行此代码来查看格式:
I could not find this anywhere. I fetch some JSON from an API that returns standard JSON dates. You can see the format by running this code in a JavaScript console:
> new Date().toJSON();
"2010-10-27T11:58:22.973Z"
嗯,实际上,我正在使用的API没有返回毫秒部分,有时它会返回一个时区而不是 Z
,因此日期可能看起来像以下任何一个:
Well, actually, the API I'm working with is not returning the millisecond part, and sometimes it returns a timezone instead of Z
, so dates can look like any one of these:
-
2010-10-27T11:58:22Z
-
2010-10-27T11:58:22 + 03:00
2010-10-27T11:58:22Z
2010-10-27T11:58:22+03:00
解析这些日期有点麻烦。有没有办法解析这些日期,使用 org.json
?
Parsing these kinds of dates is somewhat cumbersome. Is there any way to parse these kinds of dates, using org.json
?
我目前的解决方案是:
public static Date parseDateTime(String dateString) {
if (dateString == null) return null;
DateFormat fmt = new SimpleDateFormat("yyyy-MM-dd HH:mm:ssZ");
if (dateString.contains("T")) dateString = dateString.replace('T', ' ');
if (dateString.contains("Z")) dateString = dateString.replace("Z", "+0000");
else
dateString = dateString.substring(0, dateString.lastIndexOf(':')) + dateString.substring(dateString.lastIndexOf(':')+1);
try {
return fmt.parse(dateString);
}
catch (ParseException e) {
Log.e(Const.TAG, "Could not parse datetime: " + dateString);
return null;
}
}
唉!
推荐答案
该DateTime格式实际上是ISO 8601 DateTime。 JSON没有为日期/时间指定任何特定格式。如果你有点谷歌,你会发现很多实现用Java来解析它。
That DateTime format is actually ISO 8601 DateTime. JSON does not specify any particular format for dates/times. If you Google a bit, you will find plenty of implementations to parse it in Java.
如果你愿意使用Java内置日期/时间/日历以外的东西课程,我也建议 Joda Time 。他们提供(在许多方面) ISODateTimeFormat
解析这些类型的字符串。
If you are open to using something other than Java's built-in Date/Time/Calendar classes, I would also suggest Joda Time. They offer (among many things) a ISODateTimeFormat
to parse these kinds of strings.
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